100=-16t^2+96t+7

Solution for 100=-16t^2+96t+7 equation:

100=-16t^2+96t+7

We move all terms to the left:

100-(-16t^2+96t+7)=0

We get rid of parentheses

16t^2-96t-7+100=0

We add all the numbers together, and all the variables

16t^2-96t+93=0

a = 16; b = -96; c = +93;
Δ = b2-4ac
Δ = -962-4·16·93
Δ = 3264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3264}=\sqrt{64*51}=\sqrt{64}*\sqrt{51}=8\sqrt{51}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-8\sqrt{51}}{2*16}=\frac{96-8\sqrt{51}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+8\sqrt{51}}{2*16}=\frac{96+8\sqrt{51}}{32}
$